SOLVED:The molar enthalpy change for the neutralization reaction: HCI (aq) + NaOH (aq) +> NaCl (aq) + HzO (I) is AH=-57.3 k/mol. This is an exothermic reaction which means heat is released.
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SOLVED:3. Given the molar enthalpy changes for the reactions below calculate the enthalpy of formation of zinc oxide_ Zno) + 2Ht(aq) ~> Zn?t(aq) + Hz (g) AH=-151 kJlmol ZnOts) + 2Ht(aq) ~>
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